How it works
Use sensible heat relation with the units stated beside the fields. This form solves for specific heat capacity; enter the known quantities in Transferred heat magnitude, Mass, Temperature difference magnitude.
Inputs and units
| Input | Example value | What to enter |
|---|---|---|
| Transferred heat magnitude | 1,800 J | Formula symbol: Q. Required unit: J. Must be greater than zero. |
| Mass | 1.5 kg | Formula symbol: m. Required unit: kg. Must be greater than zero. |
| Temperature difference magnitude | 3 K | Formula symbol: ΔT. Required unit: K. Must be greater than zero. |
Worked example
Show example inputs and results
This example is generated by the same calculation engine using the starting values in the form. Your own inputs produce your own result.
- Transferred heat magnitude
- 1,800 J
- Mass
- 1.5 kg
- Temperature difference magnitude
- 3 K
Complete example results
- Specific heat capacity
- 400 J/(kg·K)
Reading the result
The result solves for specific heat capacity from the entered quantities. Check the result unit and the formula conditions before using it.
Questions and answers
Can I use the example values for my own calculation?
The example values illustrate the calculation. Replace every input with your own information, especially dates, rates and the selected operation.
When can I use the specific heat capacity result?
This model uses positive magnitudes. There is no phase change and specific heat is constant. Temperature difference is in kelvin or equivalent Celsius degrees, not absolute temperature.
Why are some results rounded?
Results display up to 8 decimal places. Calculations use the unrounded values; very small values use scientific notation. JavaScript floating-point arithmetic can introduce tiny rounding differences.
Are my inputs sent to a server?
The calculator processes inputs in your browser. Its code does not send your values to a server.
Method sources: openstax.org