How it works
Use magnetic inductor energy with the units stated beside the fields. This form solves for energy; enter the known quantities in Inductance, Current magnitude.
Inputs and units
| Input | Example value | What to enter |
|---|---|---|
| Inductance | 1.125 H | Formula symbol: L. Required unit: H. Must be greater than zero. |
| Current magnitude | 3 A | Formula symbol: I. Required unit: A. Must be greater than zero. |
Worked example
Show example inputs and results
This example is generated by the same calculation engine using the starting values in the form. Your own inputs produce your own result.
- Inductance
- 1.125 H
- Current magnitude
- 3 A
Complete example results
- Energy
- 5.0625 J
Reading the result
The result solves for energy from the entered quantities. Check the result unit and the formula conditions before using it.
Questions and answers
Can I use the example values for my own calculation?
The example values illustrate the calculation. Replace every input with your own information, especially dates, rates and the selected operation.
When can I use the energy result?
This model uses positive magnitudes. Use an ideal linear inductor. Core saturation, hysteresis and series resistance losses are excluded.
Why are some results rounded?
Results display up to 8 decimal places. Calculations use the unrounded values; very small values use scientific notation. JavaScript floating-point arithmetic can introduce tiny rounding differences.
Are my inputs sent to a server?
The calculator processes inputs in your browser. Its code does not send your values to a server.
Method sources: openstax.org