How it works
Convert temperature to kelvin and volume to cubic metres before entering them: 25 litres is 0.025 m³. One mole at 300 K in 0.025 m³ gives about 99,773.55141784 Pa. The model treats the gas as ideal and returns absolute pressure, not pressure above the surroundings. Real gases can deviate, especially near condensation or at high pressure.
Inputs and units
| Input | Example value | What to enter |
|---|---|---|
| Amount of gas | 1 mol | Required unit: mol. Use a non-negative value. |
| Absolute temperature | 300 K | Required unit: K. Must be greater than zero. |
| Gas volume | 0.025 m³ | Required unit: m³. Must be greater than zero. |
Worked example
Show example inputs and results
This example is generated by the same calculation engine using the starting values in the form. Your own inputs produce your own result.
- Amount of gas
- 1 mol
- Absolute temperature
- 300 K
- Gas volume
- 0.025 m³
Complete example results
- Absolute pressure
- 99,773.55141784 Pa
Reading the result
Check the units used in the formula together. The result follows the stated ideal model and supplied constants; material, environment and losses are included only where the inputs or method explicitly define them.
Questions and answers
Can I use the example values for my own calculation?
The example values illustrate the calculation. Replace every input with your own information, especially dates, rates and the selected operation.
Can I enter Celsius directly in the temperature field?
No. Add 273.15 to a Celsius reading to obtain kelvin. The ideal-gas equation requires a positive absolute temperature and a positive volume.
Why are some results rounded?
Results display up to 8 decimal places. Calculations use the unrounded values; very small values use scientific notation. JavaScript floating-point arithmetic can introduce tiny rounding differences.
Are my inputs sent to a server?
The calculator processes inputs in your browser. Its code does not send your values to a server.
Method sources: openstax.org · nist.gov